Finite Math Examples

$23000 = p {(1 + 0.015)}^{3}$

Step 1

Rewrite the equation as $p {(1 + 0.015)}^{3} = 23000$ .

$p {(1 + 0.015)}^{3} = 23000$

Step 2

Add $1$ and $0.015$ .

$p \cdot {1.015}^{3} = 23000$

Step 3

Divide each term in $p \cdot {1.015}^{3} = 23000$ by ${1.015}^{3}$ and simplify.

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Step 3.1

Divide each term in $p \cdot {1.015}^{3} = 23000$ by ${1.015}^{3}$ .

$\frac{p \cdot {1.015}^{3}}{{1.015}^{3}} = \frac{23000}{{1.015}^{3}}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of ${1.015}^{3}$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{p \cdot {1.015}^{3}}{{1.015}^{3}} = \frac{23000}{{1.015}^{3}}$

Step 3.2.1.2

Divide $p$ by $1$ .

$p = \frac{23000}{{1.015}^{3}}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Raise $1.015$ to the power of $3$ .

$p = \frac{23000}{1.04567837}$

Step 3.3.2

Divide $23000$ by $1.04567837$ .

$p = 21995.29085604$